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Remove UBSAN issues discovered via fuzzing tests.
The arithmetic conversions in C say that if a binary operator has an unsigned and signed type as operands and the unsigned type has a greater rank then the signed value is converted to unsigned. This is bad if the signed value is negative. There are a few places in the code which have this situation; convert the signed value to positive and add instead of subtracting. Reported by He Jingxuan <jingxuan.he@inf.ethz.ch> * src/read.c (find_map_unquote): Use a positive int in memmove(). (find_char_unquote): Ditto. (find_percent_cached): Ditto.
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1 changed files with 18 additions and 6 deletions
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src/read.c
24
src/read.c
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@ -2354,8 +2354,12 @@ find_map_unquote (char *string, int stopmap)
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string_len = strlen (string);
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/* The number of backslashes is now -I.
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Copy P over itself to swallow half of them. */
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memmove (&p[i], &p[i/2], (string_len - (p - string)) - (i/2) + 1);
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p += i/2;
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{
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/* Avoid arithmetic conversion of negative values to unsigned. */
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int hi = -(i/2);
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memmove (&p[i], &p[i/2], (string_len - (p - string)) + hi + 1);
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p += i/2;
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}
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if (i % 2 == 0)
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/* All the backslashes quoted each other; the STOPCHAR was
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unquoted. */
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@ -2397,8 +2401,12 @@ find_char_unquote (char *string, int stop)
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string_len = strlen (string);
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/* The number of backslashes is now -I.
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Copy P over itself to swallow half of them. */
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memmove (&p[i], &p[i/2], (string_len - (p - string)) - (i/2) + 1);
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p += i/2;
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{
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/* Avoid arithmetic conversion of negative values to unsigned. */
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int hi = -(i/2);
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memmove (&p[i], &p[i/2], (string_len - (p - string)) + hi + 1);
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p += i/2;
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}
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if (i % 2 == 0)
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/* All the backslashes quoted each other; the STOPCHAR was
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unquoted. */
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@ -2523,8 +2531,12 @@ find_percent_cached (const char **string)
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/* The number of backslashes is now -I.
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Copy P over itself to swallow half of them. */
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memmove (&pv[i], &pv[i/2], (slen - (pv - new)) - (i/2) + 1);
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p += i/2;
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{
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/* Avoid arithmetic conversion of negative values to unsigned. */
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int hi = -(i/2);
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memmove (&pv[i], &pv[i/2], (slen - (pv - new)) + hi + 1);
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p += i/2;
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}
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/* If the backslashes quoted each other; the % was unquoted. */
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if (i % 2 == 0)
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