salsa/salsa-2022-tests/tests/compile-fail/specify-does-not-work-if-the-key-is-a-salsa-input.rs
XFFXFF f7519acb13 add a test for specify
`specify` does not work if the key is a `salsa::interned`
2022-08-27 07:51:35 +08:00

35 lines
658 B
Rust

//! Test that `specify` does not work if the key is a `salsa::input`
//! compilation fails
#![allow(warnings)]
#[salsa::jar(db = Db)]
struct Jar(MyInput, MyTracked, tracked_fn);
trait Db: salsa::DbWithJar<Jar> {}
#[salsa::input(jar = Jar)]
struct MyInput {
field: u32,
}
#[salsa::tracked(jar = Jar)]
struct MyTracked {
field: u32,
}
#[salsa::tracked(jar = Jar, specify)]
fn tracked_fn(db: &dyn Db, input: MyInput) -> MyTracked {
MyTracked::new(db, input.field(db) * 2)
}
#[salsa::db(Jar)]
#[derive(Default)]
struct Database {
storage: salsa::Storage<Self>,
}
impl salsa::Database for Database {}
impl Db for Database {}
fn main() {}